用python提取sitemap网址并主动提交

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将程序和sitemap.xml放在同一目录下后运行程序即可，获取链接放在最下面了

import re
from time import sleep
import requests

try:
    with open(r'sitemap.xml', 'r', encoding='UTF-8') as f:
        a = f.read()
        p = re.compile(r'https://(.+)</loc>')
        r = p.findall(a)
        data = '\n'.join(r)
        site = input('请输入网址：')
        token = input('请出入准入密钥：')

        url = f'http://data.zz.baidu.com/urls?site={site}&token={token}'  # 记得修改成自己的网址和token

        a = requests.post(url, data=data)
        print(a.text)
        sleep(3)
except FileNotFoundError:
    print('请将sitemap.xml和本程序放在同一目录下')
    sleep(3)